It is given that tan (x + y) = x. To determine` dy/dx` use implicit differentiation.
`sec^2(x + y)*(1 + dy/dx) = 1`
=> `1 + dy/dx = 1/(sec^2(x + y))`
=> `1 + dy/dx = cos^2(x + y)`
=> `dy/dx = cos^2(x + y) - 1`
=> `dy/dx = -sin^2(x + y)`
The derivative `dy/dx = -sin^2(x + y)`
See eNotes Ad-Free
Start your 48-hour free trial to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.
Already a member? Log in here.