We have to find the derivative of y = (x+3)^2 + 2(x+3)(x-4) + (x-4)^2
y = (x+3)^2 + 2(x+3)(x-4) + (x-4)^2
Use the relation [x^n]' = n*x^(n - 1) and the chain rule
y' = 2( x + 3) + 2*( x + 3) + 2* ( x - 4)...
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We have to find the derivative of y = (x+3)^2 + 2(x+3)(x-4) + (x-4)^2
y = (x+3)^2 + 2(x+3)(x-4) + (x-4)^2
Use the relation [x^n]' = n*x^(n - 1) and the chain rule
y' = 2( x + 3) + 2*( x + 3) + 2* ( x - 4) + 2*(x - 4)
=> 2x + 6 + 2x + 6 + 2x - 8 + 2x - 8
=> 8x - 4
The required derivative is 8x - 4