We are given that the mean is 80 and the standard deviation is 6. We want to determine the score that is the cut score at 95%.

**To find the `z` score that has 5% above and 95% below, we consult the standard normal table or technology to find `z~~1.6449`** (Using a TI-83 graphing calculator)

The score that corresponds to this `z` score can be found as follows:

`z=(x-bar(x))/sigma`

`1.6449=(x-80)/6`

`9.8697=x-80`

`x=89.8697`

**So a score of `x~~90` will be above 95% of the scores.**

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now