determine the equation of the tangent to the curve defined by y=2e^x/(1+e^x) at the point (0,1)
To find the slope of the line tangent, we will need to differentiate the function.
Now we will evaluate that at the point (0,1), which means we will be plugging in 0 for x.
Now we will find the equation of the line by using slope m=1/2 and the point (0,1)
`y-1=(1/2)(x-0) => y=(1/2)x+1`