We have to find the complex number z given that (3z - 2z')/6 = -5
Let z = a + ib, z' = a - ib
(3z - 2z')/6 = -5
=>(3(a + ib) - 2(a - ib)) = -30
=> 3a + 3ib - 2a + 2ib = -30
=> a + 5ib = -30
We see that for the imaginary part 5ib there is no equivalent on the right hand side, so b = 0
a = -30
The number z = -30
We’ll help your grades soar
Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.
- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support
Already a member? Log in here.
Are you a teacher? Sign up now