We have to find the complex number z given that (3z - 2z')/6 = -5

Let z = a + ib, z' = a - ib

(3z - 2z')/6 = -5

=>(3(a + ib) - 2(a - ib)) = -30

=> 3a + 3ib - 2a + 2ib = -30

=> a + 5ib = -30

We see that for the imaginary part 5ib there is no equivalent on the right hand side, so b = 0

a = -30

**The number z = -30**

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