# derivative y=sin(e^(3x-x^2))? show how

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### 1 Answer

You need to use chain rule to find derivative of function.

The chain rule tells that you need to differentiate with respect to x, from outside toward inside, such that:

`dy/dx = (sin(e^(3x-x^2)))'*(e^(3x-x^2))'*(3x-x^2)'`

`dy/dx = (cos(e^(3x-x^2)))*(e^(3x-x^2))*(3- 2x)`

**Hence, the derivative of function is `dy/dx = (3- 2x)*(e^(3x-x^2))*(cos(e^(3x-x^2)))` **