# Derivate 1/(t^2-1)=f(t)?

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### 1 Answer

You need to find the derivative of the function `f(t)` , hence, you need to use quotient rule, such that:

`f'(t) = (1'(t^2 - 1) - 1*(t^2 - 1)')/((t^2-1)^2)`

`f'(t) = (0*(t^2 - 1) - 1*(2t))/((t^2-1)^2)`

`f'(t) = (0 - 2t)/((t^2-1)^2)`

`f'(t) = (-2t)/((t^2-1)^2)`

**Hence, evaluating the derivative of the given function yields,using the quotient rule, **`f'(t) = (-2t)/((t^2-1)^2).`