Decomposition of hydrogen peroxide: 2H2O2 --> O2(g) + 2H2O(l)  How many molecules of water are produced from the decomposition of 3.4g of hydrogen peroxide, H2O2? 

1 Answer | Add Yours

ncchemist's profile pic

ncchemist | eNotes Employee

Posted on

We are looking at the decomposition of hydrogen peroxide into water and oxygen gas: 

2H2O2 --> 2H2O + O2

We are starting with 3.4 g of H2O2.  First we need to convert this to moles.  The molecular weight of H2O2 is 34 g/mol

3.4 g * (1 mol/34 g) = 0.1 moles H2O2

From the chemical equation we see that every mole of H2O2 produces an equivalent mole of H2O, so 0.1 moles of H2O2 produces 0.1 moles of H2O.  We know that 1 mole of a substance is equivalent to Avogadro's number (6.022 x 10^23) of the molecules of the substance.  So we multiply the number of moles by Avogadro's number.

0.1 moles * (6.022 x 10^23 molecules/mole) = 6.022 x 10^22 molecules of water

The answer is 6.022 x 10^22 molecules of H2O.

We’ve answered 318,932 questions. We can answer yours, too.

Ask a question