The given question can be represented as a figure as shown in the attachment.

Let h be the height of the balloon above the river.

x be the distance of the balloon from the sailboat and y be the distance between the sail boat and the canoe where y=s+t (from the figure).

Given that the distance between the balloon and the canoe is 650m.

Now we know that,

` sin\theta=\frac{Opposite\ side}{Hypotenuse} `

So we can write,

` sin29^0=\frac{h}{650} `

i.e.

` h=650sin29^0=650\times 0.4848=315.12\ m `

Now similarly,

`sin48^0=\frac{h}{x} `

i.e.

`x=\frac{h}{sin48^0}=\frac{315.12}{0.7431}=424.06\ m `

Now we know that,

`tan\theta=\frac{Opposite\ side}{Adjacent \ side} `

So we can write,

`tan48^0=\frac{h}{s}=\frac{315.12}{s} `

i.e.

` s=\frac{315.12}{tan48^0}=\frac{315.12}{1.111}= 283.64\ m`

And,

`tan29^0=\frac{h}{t}=\frac{315.12}{t} `

i.e.

` t=\frac{315.12}{tan29^0}=\frac{315.12}{0.5543}=568.50\ m `

Finally,

`y=s+t=283.64+568.50=852.14\ m `

Hence we have the answers as:

**a) Height of the balloon = h = 315.12 m**

** b) Distance between the balloon and the sailboat = x = 424.06 m **

** c) Distance between the sailboat and the canoe = y = 852.14 m **