Solve the equation for y
`A=int^2_-2 pi(sqrt(4-x^2))^2 dx = int^2_-2 pi(4-x^2)dx = pi(4x-1/3x^2)|^2_-2`
The curve x^2 + y^2 - 4 = 0 is rotated about the x-axis. It is assumed you are referring to the volume enclosed by the shell formed by the curve as it is rotated 360 degrees about the x-axis.
x^2 + y^2 - 4 = 0
=> x^2 + y^2 = 2^2
This is the equation of a circle with center (0, 0) and radius 4. The x-axis or y = 0 is a line along a diameter of the circle. If the circle is rotated about this line by 360 degrees the resulting shape is that of a sphere with radius equal to 2.
The volume of a sphere with radius 2 is given by `V = (4/3)*pi*r^3`
Substituting r = 2
`V = (4/3)*pi*2^3`
=> `V = (4/3)*pi*8`
=> `V = (32/3)*pi`
The volume of the solid enclosed by the curve x^2 + y^2 - 4 = 0 where it is rotated about the x-axis is `(32/3)*pi`