A curve is such thatdy/dx = 5-8/x^2. The line 3y + x = 17 is the normal to the curve at the point P on thecurve. Given that the x-coordinate of P is positive, B) ﬁnd the equation of the curve
From part A) we have found that the cordinates of P is (2,5).
`y = 5x-8/x+C` Where C is constant.
This goes through point P. So the curve should satisfy x and y cordinates of P.
P = (2,5)
`5= 5xx2 – 8/2 +C`
So the equation of the curve is;
Please accept the correction for mistype.
`5 = 5xx2-8/2+C`
`5 = 10-4+C`
`C = -1`