# A cube is measured and each side is found to be 18 inches with a possible error of at most 0.005 inches. What is the approximate error in computing the volume of the cube.

You need to come up with the following notation to the side of the cube such that:

x = side of cube

You need to remember the formula that gives the volume of the cube:

`V(x) = x^3`

You need to differentiate the function of volume with respect to x such that:

`(dV(x))/(dx) = (d(x^3))/(dx)`

`dV = 3x^2 dx`

The problem provides the information that the length of the side of cube is of 18 inches and the error is of 0.005 inches such that:

`dV = 3*18^2*0.005 = 4.86`

Hence, evaluating the approximate error in computing the volume of the cube yields `dV = 4.86` .

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