_Cu +_AgNO3 -> _Cu(NO3)2+_Ag

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txmedteach's profile pic

txmedteach | High School Teacher | (Level 3) Associate Educator

Posted on

You can do this one quite simply by going atom by atom or polyatomic ion by polyatomic ion.

So, we'll see how many of each are on each side of the equation:

Cu: 1 in reactants, 1 in products

Ag: 1 in reactants, 1 in products

NO3: 1 in reactants, 2 in products

We see that we have to start the process by doubling whatever compound had NO3. We'll have to double the AgNO3 to get the following:

Cu: 1 in reactants, 1 in products

Ag: 2 in reactants, 1 in products

NO3: 2 in reactants, 2 in products

Now, we have a discrepancy with Ag, but on the products side, so we'll double the term with Ag, which is thankfully just Ag. We then end up balanced.

Cu: 1 in reactants, 1 in products

Ag: 2 in reactants, 2 in products

NO3: 2 in reactants, 2 in products

So, we'll just insert the numbers into the equation for the two portions we had to double. We end up with the following as our final solution:

Cu + 2 AgNO3 -> Cu(NO3)2 + 2 Ag

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atyourservice | Student, Grade 11 | (Level 3) Valedictorian

Posted on

_Cu +_AgNO3 -> _Cu(NO3)2+_Ag

               Reactants      Product
Cu              1                  1
Ag              1                  1
NO3            1                  2
 
We need to have an equal amount of each, since we need 2 NO3s in the reactants we put a 2 in front of the equation:
_Cu +2AgNO3 -> _Cu(NO3)2+_Ag
               
               Reactants      Product
Cu              1                  1
Ag              2                  1
NO3            2                  2
Now we need to have 2 Ag on the product side so we put a 2 there:
 
_Cu +2AgNO3 -> _Cu(NO3)2+2Ag
 
 
               Reactants      Product
Cu              1                  1
Ag              2                  2
NO3            2                  2
 
there, so the answer is Cu +2AgNO3 -> Cu(NO3)2+2Ag
udonbutterfly's profile pic

udonbutterfly | Student, College Freshman | (Level 1) Valedictorian

Posted on

_Cu +_AgNO3 -> _Cu(NO3)2+_Ag

With this reaction we have to treat the polyatomic ion as a whole as apposed to just one element.

So on the reaction side we have

1 Cu

1Ag

1 NO3

On the product side we have

1 Cu

2 NO3

1 Ag

_Cu +2AgNO3 -> _Cu(NO3)2+_Ag

We want to add 2 NO3 first. This will give you 2 Ag as well which you will have to mirror on the product side.

Cu +2AgNO3 -> Cu(NO3)2+2Ag

The reaction is now balanced! There is 1 cu on both sides 2 Ag and 2 NO3 on both sides.

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