# `csc(cos^-1 (sqrt(3)/2))` Find the exact value of the expression. (Hint: Sketch a right triangle.)

*print*Print*list*Cite

Student Comments

loves2learn | Student

First, find the inner expression.

Set `cosx=-sqrt3/2 ` because we need to find what value of x yields `-sqrt3/2 `

Use a unit circle to find this value

=> `x=(5pi)/6 `

Draw a triangle,

Given the problem and using cos rules, we know that short leg is 1, the long leg is `-sqrt3 ` and the hypotenuse is 2.

Therefore, find

=> `csc((5pi)/6)`

Using the triangle,

=> `2/1 `

This simplifies,

=> `2 `

Refer to the link for the triangle.