`csc(arctan(-5/12))` Find the exact value of the expression. (Hint: Sketch a right triangle.)

balajia | Student

`csc(tan^-1(-5/12)) = -csc(tan^-1(5/12))`

Taking 5 as opposite side and 12 as adjacent side ,then the hypotenuse will be `sqrt(12^2+5^2)=13.`

`tan^-1(5/12)=csc^-1(13/5)`

`csc(tan^-1(-5/12))=-csc(csc^-1(13/5))=-13/5=-2.6`

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