On a smooth surface, a mass `m_1=2 kg` is attached to the first object by a spring with spring constant `k_1=4 N/m` . Another mass `m_2=1 kg` is attached to the first object by a spring with spring constant `k_2=2 N/m` . The objects are aligned horizontally so that the springs are their natural lengths. If both objects are displaced `3 m` to the right of their equilibrium positions and then released, what are the equations of motion for the two objects?

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The force on block 1 from the first spring is


Where `x` is the position to the right of the equilibrium position. Let y be the distance to the right of block 2's equilibrium position. Then the second spring exerts a force `F_2` on block 1 given by


Think about it. If `x=y` there should be no force from spring 2. Also if `ygtx` then there should be a pull to the right (positive) on block 1. If `xlty` then the block should pull to the left (negative).

Since block 2 is only attached to spring 2, from Newton's third law


Now apply Newton's second law to both the blocks.

`m_1 (d^2x)/dt^2=F_1+F_2=-k_1x+k_2(y-x)`

`m_2 (d^2y)/dt^2=F_3=-k_2(y-x)`

Plug in the values for `k` and `m` , then move the terms to the left hand side.



I'm going to set let `D:=d/dt` and solve this system of equations by the elimination method.

`(1):-gt (2D^2+6)x-2y=0`

`(2):-gt (D^2+2)y-2x=0`

Now multiply eq. `(1)` by `(D^2+2)` and multiply eq. `(2)` by `2` .


`(2):-gt 2(D^2+2)y-4x=0`

Add eq. `(1)` and eq. `(2)` together to eliminate `y`

`(D^2+2)(2D^2+6)x-2(D^2+2)y+2(D^2+2)y-4x=0 `



`(3):-gt 2(d^4x)/(dt^4)+10(d^2x)/(dt^2)+8x=0`

Try a solution of the form `x(t)=e^(rt)` .

Then eq. `(3)` takes the form


Solve for the roots of this characteristic equation.



The roots are `r=i, -i, 2i, -2i` .

Using Euler's formula, it follows that two linearly independent solutions are



The general solution is a superposition of the imaginary and real parts of the linearly independent solutions.


`x(t)=a_1cos(t)+a_2sin(t)+a_3cos(2t)+a_4sin(2t) `

To find `y(t)` use earlier equation to put `y` in terms  of `x` ,



Differentiate the general solution for `x(t)` twice and plug it in. You will find


To determine the coefficients apply the initial conditions:





This will yield a system of 4 equations. You should find that,



x(t) is in black and y(t) in red.

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