# The cost of 2 pants and 5 shirts is \$211. What is the cost of one shirt if the shirt costs 40 dollars more than the pants?

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

Let the cost of a shirt be S and the cost of the pants be P.

The cost of 2 pants and 5 shirts is \$211

=> 2P + 5S = 211 ...(1)

The shirts cost \$40 more than the pants.

=> S = P + 40

=> P = S - 40

substituting in (1)

=> 2(S - 40) + 5S = 211

=> 2S  - 80 + 5S = 211

=> 7S = 291

=> S = \$41.57

One shirt cost \$41.57

hala718 | High School Teacher | (Level 1) Educator Emeritus

Posted on

Let the cost of the pants be P and the cost of the shirts be S.

Given that the cost of 2 pants and 5 shirts is 211

==> 2P + 5S = 211............(1)

Also, given that the shirt costs 40 than the pants.

==> S = P + 40 ............(2)

Now we will substitute (2) into (1).

==> 2P + 5(p+40) = 211

==> 2p + 5p + 200= 211

==> 7p = 11

==> p = 11/7 = 1.57

==> S = 41.57

Then the cost of the shirt is 41.57 dollars.

alinnne | Student, Undergraduate | (Level 3) eNoter

Posted on

the shirts costs 40 more than the pants