# The cost of 2 pants and 5 shirts is $211. What is the cost of one shirt if the shirt costs 40 dollars more than the pants?

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Let the cost of a shirt be S and the cost of the pants be P.

The cost of 2 pants and 5 shirts is $211

=> 2P + 5S = 211 ...(1)

The shirts cost $40 more than the pants.

=> S = P + 40

=> P = S - 40

substituting in (1)

=> 2(S - 40) + 5S = 211

=> 2S - 80 + 5S = 211

=> 7S = 291

=> S = $41.57

**One shirt cost $41.57**

Let the cost of the pants be P and the cost of the shirts be S.

Given that the cost of 2 pants and 5 shirts is 211

==> 2P + 5S = 211............(1)

Also, given that the shirt costs 40 than the pants.

==> S = P + 40 ............(2)

Now we will substitute (2) into (1).

==> 2P + 5(p+40) = 211

==> 2p + 5p + 200= 211

==> 7p = 11

==> p = 11/7 = 1.57

==> S = 41.57

**Then the cost of the shirt is 41.57 dollars.**

the shirts costs 40 more than the pants