`cos[(pi/2) - x]/sin[(pi/2) - x] = tan(x)` Verfiy the identity.

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Chapter 5, 5.2 - Problem 34 - Precalculus (3rd Edition, Ron Larson).
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mathace | (Level 3) Assistant Educator

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Verify the identity: `[cos[(pi/2)-x]]/[sin[(pi/2)-x]]=tanx`

Simplify the left side of the equation using the cofunction identity.

`sin(x)/cos(x)=tanx`

Simplify the left side of the equation using the quotient identity.

`tanx=tanx`

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