`cos[(pi/2) - x]/sin[(pi/2) - x] = tan(x)` Verfiy the identity.

Expert Answers
mathace eNotes educator| Certified Educator

Verify the identity: `[cos[(pi/2)-x]]/[sin[(pi/2)-x]]=tanx`

Simplify the left side of the equation using the cofunction identity.

`sin(x)/cos(x)=tanx`

Simplify the left side of the equation using the quotient identity.

`tanx=tanx`