`cos(2x) - cos(x) = 0` Find the exact solutions of the equation in the interval [0, 2pi).

Expert Answers

An illustration of the letter 'A' in a speech bubbles

`cos(2x)-cos(x)=0 , 0<=x<=2pi`

using the identity `cos(2x)=2cos^2(x)-1`

`cos(2x)-cos(x)=0`

`2cos^2(x)-1-cos(x)=0`

Let cos(x)=y,

`2y^2-y-1=0`

solving using the quadratic formula,

`y=(1+-sqrt((-1)^2-4*2(-1)))/(2*2)`

`y=(1+-sqrt(9))/4=(1+-3)/4=1,-1/2`

`:. cos(x)=1, cos(x)=-1/2`

cos(x)=-1/2

General solutions are,

`x=(2pi)/3+2pin, x=(4pi)/3+2pin`

Solutions for the range `0<=x<=2pi` are,

`x=(2pi)/3 , x=(4pi)/3`

cos(x)=1

General solutions are,

`x=0+2pin`

solutions for the range `0<=x<=2pi`  are,

`x=0 , x=2pi`

combine all the solutions ,

`x=0, x=2pi , x=(2pi)/3 , x=(4pi)/3`

 

Approved by eNotes Editorial Team

Posted on

Soaring plane image

We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

  • 30,000+ book summaries
  • 20% study tools discount
  • Ad-free content
  • PDF downloads
  • 300,000+ answers
  • 5-star customer support
Start your 48-Hour Free Trial