`cos^2(beta) + cos^2(pi/2 - beta) = 1` Verfiy the identity.

Textbook Question

Chapter 5, 5.2 - Problem 43 - Precalculus (3rd Edition, Ron Larson).
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Borys Shumyatskiy | College Teacher | (Level 3) Associate Educator

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`cos(pi/2-b)=sin(b)` for all b.

So the initial identity is equivalent to

`cos^2(b)+sin^2(b)=1,`

which is true.

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