Convert 48 grams of oxygen to liters at STP.

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At STP (standard temperature and pressure), an ideal gas occupies 22.4 liters per mole. 

Here we have 48 g of oxygen gas or O2, each molecule of which consists of two atoms of the oxygen element.

Since oxygen (O) has an atomic mass of 16 g, oxygen gas (O2) has...

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At STP (standard temperature and pressure), an ideal gas occupies 22.4 liters per mole. 

Here we have 48 g of oxygen gas or O2, each molecule of which consists of two atoms of the oxygen element.

Since oxygen (O) has an atomic mass of 16 g, oxygen gas (O2) has a molecular mass of 2 x 16 = 32 g. 

We need to convert the given amount of oxygen gas to moles and this can be done by dividing the given mass by the molecular weight of oxygen gas.

Hence, moles of oxygen gas = 48 g / 32 g/mole = 1.5 moles.

Since each mole occupies 22.4 liters at STP conditions, 1.5 moles of oxygen gas will occupy 1.5 x 22.4 = 33.6 liters.

Thus, at STP, 48 g oxygen will occupy 33.6 liters.

Hope this helps.

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