The force exerts a deceleration on the body and it can be found by,

`F = ma`

`50 = 20 xx a`

`a = 2.5 ms^(-2)`

The deceleration is `2.5 ms^(-2).`

To find the time taken to stop the mass, we can use, v = u+at

`0 =...

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The force exerts a deceleration on the body and it can be found by,

`F = ma`

`50 = 20 xx a`

`a = 2.5 ms^(-2)`

The deceleration is `2.5 ms^(-2).`

To find the time taken to stop the mass, we can use, v = u+at

`0 = 15 -2.5t`

`t = 15/2.5`

`t = 6 s.`

**Therefore, it would take 6 seconds to stop the mass.**