# Consider the sequence a_n = ((-1)^n)/(sqrt(n)) What is the limit as n approaches infinity of a_n ?

Rico Grant | Certified Educator

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We can use the fact that if `lim_(n->oo)|a_n|=0` then `lim_(n->oo)a_n=0`

(We can use the squeeze theorem; since `-|a_n|<=a_n<=|a_n| ` the result holds.)

So `lim_(n->oo)|((-1)^n)/sqrt(n)|=lim_(n->oo)1/sqrt(n)` . For `n>=1` this function is...

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