Consider the linear system x+3y+kz=-5 kx+(3+3k)y+(6+k^2)z=-11 x+4y+k^2z=k-4 For which values of k does this system have one solution?

pramodpandey | Student




det(A)`!=0 ` if (k-2)(k+1)`!=0 `

`i.e x!=-1,2`

so rank of A =3

and rank of augument matrix =3 for all values of k.

if rank (A)=rank(A|b)=3 ,then system has unique solution .

system has unique solution for all values of k except -1,2 .