# A concave mirror magnifies an object placed 30.0cm from the mirror by a factor of +3.0. Calculate the radius of curvature of the mirror.

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There are two important kinds of equations that are used when analyzing the effects of curved mirrors...**Mirror Equation:** `(1/f) = (1/(di)) + (1/(do))`

"f" represents *focal length*"di" represents

*image distance*(the distance between the mirror and image)

"do" represents

*object distance*(the distance between the mirror and the object)

**Magnification Equations:** `M = ((hi)/(ho))` ** **OR `M = (-(di)/(do))` OR `((hi)/(ho)) = (-(di)/(do))`

"M" represents *magnification*"hi" represents

*image height*

"ho" represents

*object height*

Since our problem mentions *radius of curvature*, it's also helpful to recall the following:

`f xx 2 = c`

"c" represents *center of curvature*

When solving this type of problem, it's a good idea to start by identifying (1) what information we're given in the problem, (2) what we're trying to find, and (3) an equation that connects everything.

**GIVEN:**

do = 30.0cm

M = +3.0

**FIND:**

c = ?

**EQUATION:**

There's only one equation that contains "c", but we don't have enough information to use it yet (because we would need to know "f", and we don't)!

Soooo, can we find "f"? The mirror equation has "f" in it, but we must know "di" and "do" to use it. We're given the value for "do", but since we don't have a value for "di", we don't have enough information to use the mirror equation yet.

Sooooooo, can we find "di"? Well "di" is present in two versions of the magnification equation. Since we don't have information about image height or object height, ignore the versions that include those variables, and use the 2nd option:

`M = (-(di)/(do))`

`(3.0) = (-(di)/(30.0cm))`

`di = -90.0cm`

Now we have enough information to use the mirror equation!

` ` `(1/f) = (1/(di)) + (1/(do))`

`(1/f) = (1/(-90.0cm)) + (1/(30.0cm))`

*remember to take the inverse so that "f" ends up in the numerator

`f = 45.0cm`

Now we have enough information to find "c"!!!

`f xx 2 = c`

`(45.0cm) xx 2 = c`

`c = 90.0cm`

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