You need to evaluate the limit, hence you should substitute oo for x in equation under limit such that:
`lim_(x-gtoo) root(3)(x^3 - 6x^2) - x`
You need to multiply and divide by conjugate to `root(3)(x^3 - 6x^2) - x` such that
`lim_(x-gtoo) (x^3 - 6x^2 - x^3)/(root(3)((x^3 - 6x^2)^2) + x*root(3)(x^3 - 6x^2) + x^2)`
You need to force factor `x^2 ` to denominator such that:
`lim_(x-gtoo) (- 6x^2)/(x^2(root(3)((1 - 6/x)^2) + root(3)(1 - 6/x) + 1)) `
`lim_(x-gtoo) (- 6)/(root(3)((1 - 6/x)^2) + root(3)(1 - 6/x) + 1)`
Substituting oo for x in limit yields:
`lim_(x-gtoo) (- 6)/(root(3)((1 - 6/x)^2) + root(3)(1 - 6/x) + 1) = -6/(root(3)((1 - 6/oo)^2) + root(3)(1 - 6/oo) + 1)`
`lim_(x-gtoo) (- 6)/(root(3)((1 - 6/x)^2) + root(3)(1 - 6/x) + 1) = -6/(1+1+1) = -6/3=-2`
Hence, evaluating the limit to the function yields `lim_(x-gtoo) root(3)(x^3 - 6x^2) - x = -2.`
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