You need to evaluate the limit, hence you should substitute oo for x in equation under limit such that:

`lim_(x-gtoo) root(3)(x^3 - 6x^2) - x`

You need to multiply and divide by conjugate to `root(3)(x^3 - 6x^2) - x` such that

`lim_(x-gtoo) (x^3 - 6x^2 - x^3)/(root(3)((x^3 - 6x^2)^2) + x*root(3)(x^3 - 6x^2) + x^2)`

You need to force factor `x^2 ` to denominator such that:

`lim_(x-gtoo) (- 6x^2)/(x^2(root(3)((1 - 6/x)^2) + root(3)(1 - 6/x) + 1)) `

`lim_(x-gtoo) (- 6)/(root(3)((1 - 6/x)^2) + root(3)(1 - 6/x) + 1)`

Substituting oo for x in limit yields:

`lim_(x-gtoo) (- 6)/(root(3)((1 - 6/x)^2) + root(3)(1 - 6/x) + 1) = -6/(root(3)((1 - 6/oo)^2) + root(3)(1 - 6/oo) + 1)`

`lim_(x-gtoo) (- 6)/(root(3)((1 - 6/x)^2) + root(3)(1 - 6/x) + 1) = -6/(1+1+1) = -6/3=-2`

**Hence, evaluating the limit to the function yields `lim_(x-gtoo) root(3)(x^3 - 6x^2) - x = -2.` **

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now