Begin with `A=P(1+i)^n`
`A/P=(1+i)^n` divide both sides by P
`root(n)(A/P)=1+i` take the `n^(th)` root of both sides
`root(n)(A/P)-1=i` subtract 1 from both sides
Thus the answer is `i=root(n)(A/P)-1`
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