# Complete and balance the following equation for H^2SO^4(aq)+KOH(aq)? Provide a net ionic equation

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`H_2SO_4_(aq)+2KOH_((aq)) rarr K_2SO_4_(aq)+2H_2O_((l))`

This is a acid-base reaction. `H_2SO_4` act as a acid and `KOH` act as a base. When they react they will form `K_2SO_4` which is a salt and water.

Since the reaction is a complete one with strong acid and strong base the resultants are fully dissolved in water and will break in to ions.

`H_2SO_4_(aq) rarr 2H^(+)_(aq)+SO_4^(2-)_(aq)`

`2KOH_(aq) rarr 2K^(+)_(aq)+2OH^(-)_(aq)`

`K_2SO_4_(aq) rarr 2K^(+)_(aq)+SO_4^(2-)_(aq)`

But in a acid base reaction;

`H^++OH^(-) rarr H_2O`

Ionic equation

`2H^(+)_(aq)+SO_4^(2-)_(aq)+2K^(+)_(aq)+2OH^(-)_(aq) rarr 2H_2O_((l))+2K^(+)_(aq)+SO_4^(2-)_(aq)`

In both sides e have common ions`(K^+, SO_4^(2-))` and factors. Canceling these common ions and factors will give you the net ionic equation.

`H^+_(aq)+OH^(-)_(aq) rarr H_2O_((l))`

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