A committe of 5  is to be chosen from 6 men and 4 women, In how many ways can this be done if there must be more men than women in the committee  

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The possibilities are for the committee are:

( 5 men and 0 women) OR ( 4 men and 1 woman) OR ( 3 men and 2 women)

Now we will determine in how many ways we could arrange each possibility.

( 5 men and 0 women) = 6*5 = 30...

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The possibilities are for the committee are:

( 5 men and 0 women) OR ( 4 men and 1 woman) OR ( 3 men and 2 women)

Now we will determine in how many ways we could arrange each possibility.

( 5 men and 0 women) = 6*5 = 30 way

(4 men and 1 woman) = 6*4 + 1*4 = 24 + 4 = 28 ways

( 3 men and 2 women) = 6*3 + 2*4 = 18 + 12 = 30 way.

Now we will add all :

==> 30 + 28 + 30 = 88 way.

Then, there are 88 ways that we can create a committee of 6 men and 4 women.

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