To answer this question, we must first identify how much oxygen is reacted with the glucose to make it burn. To start, I will write the chemical equation, but with variables for the unknown quantities.
C6H12O6 + xO2 => yCO2 + zH2O
Here, x, y, and z are the variables. I will start balancing with the carbon. Because there are 6 carbon in the glucose, there...
(The entire section contains 207 words.)
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