*We are given a circle with diameter 20in, and we want to cut a rectangle out of it; the vertices of the rectangle lie on the circle and the area of the rectangle is 60 sq in.*

(1) Note that if a rectangle is inscribed in a circle, opposite vertices...

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*We are given a circle with diameter 20in, and we want to cut a rectangle out of it; the vertices of the rectangle lie on the circle and the area of the rectangle is 60 sq in.*

(1) Note that if a rectangle is inscribed in a circle, opposite vertices lie on a diagonal. (If a right angle is inscribed in a circle, the sides of the angle intercept the circle at the endpoints of a diameter)

So the diagonal of the rectangle has length 20 in

(2) `l*w=60 => w=60/l`

(3) From the pythagorean theorem we also have `60^2=l^2+w^2 => 3600=l^2+(60/l)^2`

Thus:

`l^2+3600/l^2=400`

`l^4-400l^2+3600=0`

This is a quadratic in `l^2` ; using the quadratic formula we get

`l^2=(400+-sqrt(400^2-4(1)(3600)))/2`

`=(400+-sqrt(145600))/2`

`~~390.7878,9.2122`

So `l~~19.78,3.04` .

Checking we see that (19.78)(3.04)=60.13 and `19.78^2+3.04^2=400.49=(20.01)^2` .

**Thus the dimensions are approximately 19.78in by 3.04in.**