What is the center and radius of the circle x^2 + y^2 - 6x + 10y + 9 = 0.

1 Answer | Add Yours

justaguide's profile pic

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

The equation x^2 + y^2 - 6x + 10y + 9 = 0 has to be expressed in the form (x-a)^2 + (y-b)^2 = r^2

x^2 + y^2 - 6x + 10y + 9 = 0

=> x^2 - 6x + 9 + y^2 + 10y + 25 = -9 + 9 + 25

=> (x - 3)^2 + (y + 5)^2 = 5^2

The center of the circle represented by x^2 + y^2 - 6x + 10y + 9 = 0 is (3, -5) and the radius is 5.

We’ve answered 318,983 questions. We can answer yours, too.

Ask a question