(a) The speed can be found using the Pythagorean theorem. Since North is orthoganal to East we have the speed as the hypotenuse of a right triangle with legs 30 and 5.

`(sp)^2=30^2+5^2==>sp=sqrt(925)=5sqrt(37)~~30.4 "km"/"hr"`

(b) We can find the angle using the right triangle. If `theta` is the angle measured off the leg running North/South we have:

`tantheta=5/30 ==> theta=tan^(-1)(1/6)~~.165` radians East of North.

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