# The Chicago White Sox won 27 few thatn twice as many games as they lost. They played 162. How many wins and loses did they have?Applications of Linear Equations

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For simplicity's sake, let's use W as the variable for wins and L as the variable for losses. We know a few things here:

W + L = 162

and

W = (2L - 27)

So now all you have to do is plug that in for W in the first equation. You do it like this:

2L - 27 + L = 162

Now you have an algebra problem that you can solve. Add 27 to both sides and you have

2L + L = 189 or 3L = 189

Divide both sides by 3 and you have

L = 63

So we know the White Sox lost 63 games.

If you plug that back into your first equation you will see that they won 99 games.

let W be the number of games the Sox won.

Let L be the number of games the Sox lost.

There are no ties, so W + L = 162, the total number of games played. So W = 162 - L

The Sox won 27 less than twice the amount they lost (2 x L), so:

2 x L - 27 = W

2L - 27 = 162 - L (plug in for W )

3L = 162 + 27 (Add L + 27 to both sides)

L = 189/3 (divide both sides by 3)

L = 63 games lost

W = 162 - L = 99 games won

By the given condition, if the number of games won is x, then the lost games is 2x+27.

Therefore the number of games games played is equal to :

games won+games lost = x+2x+27 which is equal to 162.So,3x+27 =162 . Or 3x= 162-27 = 135. Or

3x=135. Or x=135/3 =45 is the number of games won.

Then the number of games lost =2x+27 = 2*45+27 = 117