The Chicago White Sox won 27 few thatn twice as many games as they lost. They played 162. How many wins and loses did they have?Applications of Linear Equations
For simplicity's sake, let's use W as the variable for wins and L as the variable for losses. We know a few things here:
W + L = 162
W = (2L - 27)
So now all you have to do is plug that in for W in the first equation. You do it like this:
2L - 27 + L = 162
Now you have an algebra problem that you can solve. Add 27 to both sides and you have
2L + L = 189 or 3L = 189
Divide both sides by 3 and you have
L = 63
So we know the White Sox lost 63 games.
If you plug that back into your first equation you will see that they won 99 games.
let W be the number of games the Sox won.
Let L be the number of games the Sox lost.
There are no ties, so W + L = 162, the total number of games played. So W = 162 - L
The Sox won 27 less than twice the amount they lost (2 x L), so:
2 x L - 27 = W
2L - 27 = 162 - L (plug in for W )
3L = 162 + 27 (Add L + 27 to both sides)
L = 189/3 (divide both sides by 3)
L = 63 games lost
W = 162 - L = 99 games won
By the given condition, if the number of games won is x, then the lost games is 2x+27.
Therefore the number of games games played is equal to :
games won+games lost = x+2x+27 which is equal to 162.So,3x+27 =162 . Or 3x= 162-27 = 135. Or
3x=135. Or x=135/3 =45 is the number of games won.
Then the number of games lost =2x+27 = 2*45+27 = 117