# In chemistry 22.4litres of gas weighs 70g at S.T.P.Calculate weight of gas if occupies volume of 20litres at 27degree celsius and 700mmHg of pressureit's a numerical of chemistry based on boyle's...

In chemistry 22.4litres of gas weighs 70g at S.T.P.Calculate weight of gas if occupies volume of 20litres at 27degree celsius and 700mmHg of pressure

it's a numerical of chemistry based on boyle's law and charles law.

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### 2 Answers

By gas law:

PV= nRT, where P is pressure of the gas at the temperature T and R is a gas constant and n is the substance of gas in moles.

Put values in the equation For STP and The given temprature and pressure situations.

760d)(22.4)=(70/200.59)R(273.15) (1)

(700d)(20)=(x/200.59)R(273.15+27) (2)

(1)/(2) eleminates R and reduces To:

760*22.4/(700*20) = (70/x)(273.15)/290.15

x=70*273.15*700*20/(290.15*760*22.4)

=** 54.17 g**

It is 54 grams, correct to the nearest number. It is based on the formula, known as the gas law, which is PV= nRT. The figures can be directly put inside and solved. The rest is up to you to decide on how do you want to proceed.