# Certain amount of gas occupies 400 ml at 17 degree C. At what temperature would the volume be reduced to half.

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### 1 Answer

Let us assume the gas can be considered to be an ideal gas. The relation between pressure P, temperature T and volume V of an ideal gas is: P*V = n*R*T, where n is the amount of gas in moles and R is a constant.

Here, the amount of gas is not changing and as R is a constant we can write the ideal gas equation as P*V/T = constant

V1 = 400 ml and T1 = 17 C or 290 K.

We need to determine the change in temperature to decrease the volume by half. The pressure is assumed to remain constant in both the cases.

400/290 = (400/2)/T2

=> T2 = 290/2

=> 145 K

or -128 degree Celsius

The gas has to be cooled to -128 degree Celsius to reduce the volume to half.