A catcher "gives" with the ball when he catches a 0.127 kg baseball moving at 29.8 m/s. If he moves his glove a distance of 4.97 cm, what is the average force acting on his hand? What is the force...

A catcher "gives" with the ball when he catches a 0.127 kg baseball moving at 29.8 m/s. If he moves his glove a distance of 4.97 cm, what is the average force acting on his hand? What is the force if the glove and hand move 12.9 cm.

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justaguide | College Teacher | (Level 2) Distinguished Educator

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The catcher "gives" with the ball when he catches a 0.127 kg baseball moving at 29.8 m/s. The average force acting on his hand has to be determined given that he moves his glove a distance of 4.97cm.

The baseball weighs 0.127 kg and is moving at 29.8 m/s when it is caught by the catcher. The kinetic energy of an object weighing m kg and traveling at v m/s is equal to KE = (1/2)*m*v^2 J.

The kinetic energy of the baseball is (1/2)*0.127*(29.8)^2 = 56.39 J

When the ball is caught by the catcher he moves his glove 4.97 cm or 0.0497 m. The average force acting on his hand is the energy in the ball divided by the distance his hand moves. This is given as F = 56.39/0.0497 = 1134.6 N

An average force of 1134.6 N acts on the hand of the catcher when he moves his hand and glove 4.97 cm when the baseball is caught.

If his hand moves 12.9 cm, the average force exerted is reduced to 56.39/0.129 = 437.13 N.

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