the cartesian coordinates of a point are given (1,-3) find the polar coordinates `(r, theta)` where `r gt0` , `0<=theta<2pi`
- print Print
- list Cite
Expert Answers
lfryerda
| Certified Educator
calendarEducator since 2012
write738 answers
starTop subjects are Math and Science
Since the point (1,-3) is in the fourth quadrant, we can find the angle `theta` using the right angled triangle with sides 1, 3 and hypotenuse `sqrt{1+9}=sqrt10` . The angle is going to then by (using the CAST rule)
`theta = 2pi - tan^{-1}(3/1)approx 5.03`
The value of r is the hypotenuse of the right angled-triangle, so `r=sqrt10` .
This means that the polar coordinates are `(r, theta)=(sqrt10, 5.03)` .
Related Questions
- What are the polar coordinates (r, theta) of the point (-1,-square root of 3) where r > 0 and...
- 1 Educator Answer
- find the exact length of the polar curve, r=(theta)^2, 0<= theta<=2pi please be as...
- 1 Educator Answer
- Graph the polar function and its tangents that are horizontal or vertical for r=`sqrt(theta),...
- 1 Educator Answer
- `f(theta) = 2sec(theta) + tan(theta), 0 < theta < 2pi` Find the critical numbers of...
- 1 Educator Answer
- What is the limit of `(x^3+y^3)/(x^2+y^2)` as (x,y)-->(0,0)? I'm supposed to use polar...
- 1 Educator Answer