a car traveling at 22.4 m/s skids to a stop in 2.55 s.  Determine the skidding distance the of the car ( assume uniform acceleration)

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aruv | High School Teacher | (Level 2) Valedictorian

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A car is traveling at a speed of  22.4 m/s and skids to a stop in 2.55 s. So we have following information:

Initial speed of the car i.e  u= 22.4 m/s

Final speed of the car  i.e.  v=0 m/s  ( because car stops)

Time taken to come to stopping position  t= 2.55 sec

We wish to determine an acceleration (which is in fact a retardation) a=?

We have equation of the motion

`v=u+at`

`0=22.4+2.55xxa`

`-2.55a=22.4`

`a=22.4/(-2.55)`

`=-8.784 ms^(-2)`

`v^2=u^2+2as`

`0=(22.4)^2+2xxsxx(-8.784)`

`-501.76=-17.568s`

`s=28.56 m`

Before car stops it will travel 28.56 m.

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