A car of mass 600 kg is travelling at 10m/s. when the brakes are applied, it comes to rest in 10 m.what is the average force exerted by the brakes?
mass of car=600 kg
initial velocity u = 10 m/s
distance s= 10m
final velocity v=0 (car stop)
By equation of motion
`a=-100/20=-5 ` m/s^2 ( retardation )
Thus by Newton's second law of motion ,retarding force is
Thus force break exert = 3000N.