if a car carried 67200L of hydrogen gas at standard pressure 14.7 psi and that volume of gas had to be squeezed into a space of 4.5 ft^3 what would the pressure have to be?

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gsenviro | College Teacher | (Level 1) Educator Emeritus

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Using the Boyle's Law, product of pressure and volume is constant (Assuming temperature to be constant), i.e.,

`P_1V_1 = P_2V_2`

Here, P1 = 14.7 psi , V1 = 67,200 lt , V2 = 4.5 ft^3

1 ft^3 = 28.32 lt

thus, V2 = 4.5 ft^3 x 28.32 lt/ft^3 = 127.44 lt

Therefore, we can calculate P2 as

`P_2 = (P_1V_1)/V_2 = (14.7 xx 67200)/(127.44)`

= 7751.4 psi

Hope this helps

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