If a wire of length L carrying a current I lies in a magnetic field B, the force on the wire due to the interaction between magnetic fields is given by F = `I*LxxB` .

A straight wire of length 160 m is carrying a current equal to 150 A....

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If a wire of length L carrying a current I lies in a magnetic field B, the force on the wire due to the interaction between magnetic fields is given by F = `I*LxxB` .

A straight wire of length 160 m is carrying a current equal to 150 A. The Earth's magnetic field is 5*10^-5 T and makes an angle 65 degrees with the wire. It is assumed that the angle between the direction of current and the magntic field is 65 degrees. In this canse the magnitude of the force on the wire is F = 150*160*5*10^-5*sin 65 =1.087 N

**The magnitude of the magnetic force acting on the wire is equal to 1.087 N**

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