# Can you explain briefly about the Telescoping Summation?

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### 1 Answer

A telescoping sum or series is a series where every term except the first few and the last few terms cancel out. This means that the series becomes very easy to turn into a closed expression.

It is not usually immediately obvious that a series will telescope, and usually some manipulation with partial fractions or other algebraic techniques may be necessary to make it a telescoping sum.

For example, consider the sum

`sum_{k=1}^n 2/{k(k+2)}`

Although it isn't a telescoping sum yet, we can use partial fractions on this sum. That is, break the terms into two fractions:

`2/{k(k+2)}=a/k+b/{k+2}`

and by finding common denominators on the RHS, we see that `a=1` and `b=-1`.

This means that the sum now becomes

`\sum_{k=1}^n(1/k-1/{k+2})`

`=(1-1/3)+(1/2-1/4)+(1/3-1/5)+\cdots+(1/n-1/{n+2})`

and rearranging the terms gives

`=1+1/2+(1/3-1/3)+(1/4-1/4)+\cdots+(1/n-1/n)-1/{n+1}-1/{n+2}`

and every term cancels out except the first two and the last two, so the final sum is just

`=1+1/2-1/{n+1}-1/{n+2}`

so this means that

`\sum_{k=1}^n 2/{k(k+2)}={n(3n+5)}/{2(n+1)(n+2)}`