# Can you balance the equation hydrochloric acid + sodium hydroxide -> sodium chloride + water? Also show how to calculate the yield in grams and in moles. For the mentioned reaction, the balanced chemical equation is:

` ` `HCl+NaOH->NaCl+H_2O`

The reactants are hydrochloric acid (HCl) and sodium hydroxide (NaOH) and the products are sodium chloride and water.

We can use the atomic masses of hydrogen, chlorine, sodium and oxygen to determine the molar masses of these compounds....

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For the mentioned reaction, the balanced chemical equation is:

` ` `HCl+NaOH->NaCl+H_2O`

The reactants are hydrochloric acid (HCl) and sodium hydroxide (NaOH) and the products are sodium chloride and water.

We can use the atomic masses of hydrogen, chlorine, sodium and oxygen to determine the molar masses of these compounds. Hydrochloric acid has a molar mass of 36.5 g/mole, sodium hydroxide has a molar mass of 40 g/mole, sodium chloride has a molar mass of 58.5 g/mole and water has a molar mass of 18 g/mole.

Using stoichiometry,

1 mole of hydrochloric acid reacts with 1 mole of sodium hydroxide to produce 1 mole of sodium chloride and 1 mole of water.

Given any mass of the reactants, we can convert it to moles and use stoichiometry to determine the moles of product that will be produced and convert it to grams.

For example, say we start with 40 g of sodium hydroxide, which is equal to 1 mole of the compound (molar mass = 40 g/mole). Using stoichiometry, 1 mole of sodium hydroxide produces 1 mole of sodium chlroide. Since the molar mass of sodium chloride is 58.5 g, we will obtain 58.5 g sodium chloride as the product.

Hope this helps.

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