The expression (2y+4)(3y+1) + (y+1)(2y-4) has to be simplified.

(2y+4)(3y+1) + (y+1)(2y-4)

=> 6y^2 + 2y + 12y + 4 + 2y^2 + 2y - 4y - 4

=> 8y^2 + 12y

**The simplified form of (2y+4)(3y+1) + (y+1)(2y-4) is 8y^2 + 12y**

((2y+4)(3y+1)) + ((y+1)(2y-4))

distribute the terms

6y^2 + 2y + 12y + 4 + 2y^2+ 2y - 4y - 4

combine like terms

8y^2 + 12y

((2y+4)(3y+1)) + ((y+1)(2y-4))

distribute the terms above to the other parenthesis you should end up with:

6y^2 + 2y + 12y + 4 + 2y^2+ 2y - 4y - 4

combine like terms and you should end up with:

8y^2 + 12y

just like how you would do above, all you do is simplify the numbers and letters that are the same. if you do the opposite, it will not work therefore, that answer will remain the same.

(2y +4)*(3y+1)+(y+1)(2y-4)

= [(6ysquare+2y)+(12y+4)]+[(2ysquare-4y)+(2y-4)]

=**8ysquare+10y**

is the answer

hope it helps u

cheers!!!