Since `h` is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.

`2h(7+5)=144 `

Divide each term in the equation by `(7+5)` .

`2h=12 `

Divide each term in the equation by `2` .

`h=6`

You need to perform the multiplication to the right side, such that:

`144 = 2*7*h + 2*5*h`

`144 = 14h + 10h`

Performing the sum of the terms that contain the unknown h, yields:

`144 = 24h`

You need to evaluate h, hence, you need to divide by 24, such that:

`h = 144/24 => h = 6`

**Hence, evaluating the value of `h, ` under the given conditions, yields `h = 6` .**

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