Solve the following system of two equations with two unknowns:
`3+2x-y=0` (1)
`-3-7y=10x` (2)
Write each equation in standard form `(ax+by=c)`.
Subtract 3 to each side of (1).
`2x-y=-3` (3)
Add 3 to each side of (2).
`-7y=10x+3` (2.1)
Subtract 10x to each side of (2.1)
`-10x-7y=3` (4)
Multiply (3)...
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Solve the following system of two equations with two unknowns:
`3+2x-y=0` (1)
`-3-7y=10x` (2)
Write each equation in standard form `(ax+by=c)`.
Subtract 3 to each side of (1).
`2x-y=-3` (3)
Add 3 to each side of (2).
`-7y=10x+3` (2.1)
Subtract 10x to each side of (2.1)
`-10x-7y=3` (4)
Multiply (3) by (5) and add to (4) to solve by elimination.
`10x-5y=-15` (5)
`-10x-7y=3`
---------------------
`-12y=-12` (6)
Divide (6) by -12 to obtain the value of y.
`y=1`
Substitute y=1 in (3)
`2x-1=-3`
Solve for x:
`2x=-3+1`
`x=-2/2=-1`
Therefore x=-1 and y=1.
Verify by substituting x=-1 and y=1 in (2)
-3-(7)(1)=10(-1)
-3-7=-10
-10=-10