Can someone please explain how to find the area of one of these trapeziums? Thanks!

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justaguide | College Teacher | (Level 2) Distinguished Educator

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The area of the first trapezium with opposite sides of length 8 cm and 10 cm, separated by a distance 6 cm can be determined in the following way. Divide the trapezium into triangles, one with side of length 8 cm as base and the other with the side of length 10 cm as base. The height for both the triangles is 6 cm.

The area of the trapezium is `(1/2)*(8*6 + 10*6) = 54` square centimeters.

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sciencesolve | Teacher | (Level 3) Educator Emeritus

Posted on

You may evaluate the area of trapesium having the large base of 7.7 cm, the small base of 6.3 cm and the height of 4.4 cm, such that:

`A = ((B + b)*h)/2`

B represents the large base

b represents the small base

h represents the vertical height

Reasoning by analogy, yields:

`A = ((7.7+6.3)*4.4)/2`

`A = (14*4.4)/2 => A = 7*4.4 => A = 30.8 cm^2`

Hence, evaluating the area of the trapezium found at the bottom of the page, using the formula `A = ((B + b)*h)/2` , yields `A = 30.8 cm^2.`

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