What is the solution of sin (θ/2) = 1/2 in the interval [0, 2*pi)
- print Print
- list Cite
Expert Answers
Rylan Hills
| Certified Educator
calendarEducator since 2010
write12,544 answers
starTop subjects are Math, Science, and Business
The solutions of the equation `sin(theta/2) = 1/2` in the interval `[0, 2*pi)` are required.
`sin(theta/2) = 1/2`
=> `theta/2 = pi/6` and `theta/2 = 5*pi/6`
=> `theta = pi/3` and `theta = 5*pi/3`
The solution of the equation in the given interval is `pi/3` and `5*pi/3`
Related Questions
- If x `sin^3 θ` `theta` + y `cos^3 θ ``theta` = sin θ cos θ, and x sin θ = y cos θ, prove that...
- 1 Educator Answer
- Find all solutions of the equation sin 2x = cos 2x, if x is in the interval [0,pi].
- 1 Educator Answer
- `(sin(2x) + cos(2x))^2 = 1` Find the exact solutions of the equation in the interval [0, 2pi).
- 1 Educator Answer
- `sin(2x) - sin(x) = 0` Find the exact solutions of the equation in the interval [0, 2pi).
- 1 Educator Answer
- `cos(x + pi/4) - cos(x - pi/4) = 1` Find all solutions of the equation in the interval [0,...
- 1 Educator Answer