Can anyone help find the derivatives of a given function? 1) y=(lnx)/(3x-1+x^2) Thank's

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To find the derivative of the function, we need to use the quotient rule.  This means that the derivative is:

`y'={(1/x)(3x-1+x^2)-lnx(3+2x)}/(3x-1+x^2)^2`   simplify numerator

`={3x-1+x^2-x(3+2x)lnx}/{x(3x-1+x^2)^2}`

The derivative is `{3x-1+x^2-x(3+2x)lnx}/{x(3x-1+x^2)^2}` .

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