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To find the derivative of the function, we need to use the quotient rule. This means that the derivative is:
`y'={(1/x)(3x-1+x^2)-lnx(3+2x)}/(3x-1+x^2)^2` simplify numerator
`={3x-1+x^2-x(3+2x)lnx}/{x(3x-1+x^2)^2}`
The derivative is `{3x-1+x^2-x(3+2x)lnx}/{x(3x-1+x^2)^2}` .
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