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To find the derivative of the function, we need to use the quotient rule. This means that the derivative is:

`y'={(1/x)(3x-1+x^2)-lnx(3+2x)}/(3x-1+x^2)^2` simplify numerator

`={3x-1+x^2-x(3+2x)lnx}/{x(3x-1+x^2)^2}`

**The derivative is `{3x-1+x^2-x(3+2x)lnx}/{x(3x-1+x^2)^2}` .**

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